If I have 0.0017 mol Mg on the reactant side of the following equation, how many moles of H2 would be produced? Mg (s) + 2 HCl (aq) → Mg Cl2(aq) + H2 (g)

Answer 1

Totally agree

.0017 moles Mg (1 mole H2/1 mole Mg)= .0017moles of H2

1 mole H2/ 1 mole Mg is the conversion factor to relate the amount in moles of one reactant or product to another

Answer 2

You have balanced the reaction and that is the first most important step! Now we see that one mole Mg produces one mole H2 . With that being said .0017 moles Mg will produce .0017 moles H2 ( because the numerical report is kept constant)

Answer 3

The chemical reaction equation:

Mg (s) + 2HCl (aq) → MgCl₂(aq) + H₂ (g)

says that 1 mole of Mg combined with 2 moles of HCl will yield 1 mole of MgCl₂ and 1 mole of hydrogen gas. The coefficient in front of each compound is the number of moles of each.

So, since 1 mole of Mg yields 1 mole of H₂, then 0.0017 moles of Mg will yield 0.0017 moles of H₂.