Please assist in drawing products for given reactions

Question

Please help in naming the resulting products for the reactions in the given image:

https://ibb.co/SNskKg5

Answer 1

This answer is sadly going to be relatively late,

The first question is going to be a Grignard reagent reacting with methyl benzanoate; the partial positivity of the carbonyl carbon leaves it susceptible to nucleophilic attack via the nucleophilic carbon in the C-Mg bond; double addition will occur on that carbon resulting in a tertiary alcohol; 2-phenylpropan-2-ol

The second question is going to be DIBAL-H reduction with H3O+ solvent, so ester -> aldehyde where the carbonyl oxygen coordinates to the aluminum and creates a hemiacetal intermediate, resulting in 2-methyl-3-phenylpropanal

The third question is going to be a reaction that involves making amides from acyl chlorides(in this case, acetyl chloride), which is a generally a simple substitution of the chloro-group, so the result is acetamide

The fourth question is a simple Fisher esterification, where the carboxylic acid is protonated by the solvent, making the C-OH more polarized, leaving it susceptible to nucleophilic attack by the alcohol; the result of this reaction is 2-ethyl methyl cyclopentanoate

The fifth question involves another reduction reaction using LiAlH4 in acidic workup, which is a strong reducing agent, turning ethyl benzanoate into phenol

The sixth question involves an acid anhydride reacting with alcohol with pyriridine solvent, which is meant to deprotonate the intermediate after the anhydride is attacked at the carbonyl, then bond cleavage would occur; two products are formed, which are methanoic acid and a ethancyclopropyl methanoate

The seventh question is another reduction reaction using LiAlH4 in acidic workup, which is a strong reducing agent, turning methanamide to ethanamine

The eighth question is basic SOCl2 reaction in which the one of the chlorines with add onto the carbonyl oxygen after having Cl as a leaving group, then deprotonation occurs to relieve the positive charge of the oxygen in the intermediate; theCl- attacks the carbonyl carbon then more elimination occurs on SOCl2 forming an acid chloride