Michael W. answered 08/09/24
Are used to work As a Sattelite operation control engineer
VA =VAx i^+VAy j^
V
B
=
V
B
x
i
^
+
V
B
y
j
^
VB =VBx i^+VBy j^
The magnitudes of these velocities can be found using:
∣
V
A
∣
=
V
A
x
2
+
V
A
y
2
∣VA ∣=VAx2 +VAy2
∣
V
B
∣
=
V
B
x
2
+
V
B
y
2
∣VB ∣=VBx2 +VBy2
Let me compute these values for you.
The velocities of each vehicle immediately after the collision are as follows:
- Vehicle A:
- Velocity in vector form: V
- A
- =
- 3.91
- i
- ^
- +
- 10.80
- j
- ^
- VA =3.91i^+10.80j^ m/s
- Magnitude: ∣
- V
- A
- ∣
- =
- 11.48
- ∣VA ∣=11.48 m/s
- Vehicle B:
- Velocity in vector form: V
- B
- =
- 2.73
- i
- ^
- +
- 5.59
- j
- ^
- VB =2.73i^+5.59j^ m/s
- Magnitude: ∣
- V
- B
- ∣
- =
- 6.22
- ∣VB ∣=6.22 m/s