Grace J.

asked • 07/22/24

Chemistry Grade 12 Question: I did half but I don't know the oxidizing agent...

Question: Aqueous hydrogen peroxide and aqueous iron (III) nitrate

Hint: This system is not acidified.


Species List: H2O(l), H2O2(l), Fe2+(aq),NO3-(aq)

Oxidizing Agents:

Reducing Agents: H2O(l), H2O2(l) SRA: H2O2(l)

Spontaneous?: YES

Reduction half-reaction: 2NO3-(aq), + 4H+(aq) + 2e- = N2O4(g) + 2H2O(l)

Oxidation half-reaction: H2O2(l) = O2(g) + 2H+(aq) + 2e-

Net Ionic Equation: 2NO3-(aq) + 4H+(aq) + H2O2(l) = N2O4(g) + 2H2O(l) + O2(g) + 2H+(aq)

J.R. S.

tutor
It is interesting that the "Hint" tells us that the system is not acidified, yet the net ionic equation shows H^+(aq) is present, and this represents acidic conditions. Are you sure you have the correct redox equation?
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07/23/24

Sean M.

Nitrogen in the NO3- (nitrate) because it goes from a +5 oxidation state to a +4 in N2O4. That means it gains 1 electron per nitrate. LEO goes GER. Lose Electrons Oxidized, Gain Electrons Reduced. Because it gains 1 electron it's reduced making it the oxidizing agent. Whatever is oxidized would be the reducing agent because it forces something to take the electron it loses. In this problem the Oxygen in H2O2. It goes from a -1 oxidation state in hydrogen peroxide (H2O2) to an oxidation state of 0 in elemental oxygen (O2). Remember all elements have oxidation states = 0. Hope that helps.
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07/23/24

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