Calculate the molarity of a solution that contains 10.0g of sucrose (C12H22O11) dissolved into a 125mL solution.

Answer 1

In order to calculate the molarity, we must use the formula M=mol/volume (liters).

1. To find the molarity, we divide the mass of the substance by the molar mass (10.0 g)/(342.2965 g/mol)=0.0292 moles sucrose
2. Since we are given the volume in mL, we must convert to L to satisfy the formula, 125mL = 0.125 L
3. Following the formula M=mol/volume, we get 0.0292 mol/0.125 L =0.2336 M

Answer 2

Molarity (M) = moles/liters

1. First determine moles of sucrose so we (10.0g)(1 mol/342.12 g) = 0.0292 mol
2. Next you need to convert 125 mL to L which is 125 mL * 1L/1000 mL = 0.125 L
3. Now calculate molarity: M = 0.0292 mol/0.125 L = 0.234 M