Vesper D.

asked • 05/07/24

What is the solubility of MgCO₃ in a solution that contains 0.060 M Mg²⁺ ions? (Ksp of MgCO₃ is 3.5 × 10⁻⁸)

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Anthony T. answered • 05/07/24

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MgCO3 is very insoluble as evidenced by its very small Ksp.

The solubility of MgCO3 at room temperature can be found by Ksp = [Mg2+] [CO32-] = X2.

Solving for X, X = √ Ksp ,  X = 1.87 x 10-4 M = MgCO3 concentration.

Since this is much smaller that the Mg2+ concentration given, this means that there is Mg2+ added from a source other than MgCO3 (common ion effect).


The added common ion decreases the solubility of MgCO3, and the resulting solubility an be obtained by the following equation:   Ksp = 0.06 x [CO32-] where the [CO3] is the resulting solubility of MgCO3.

[CO32-]  = Ksp / 0.06 = 5.83 x 10-7 M.


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