how many grams of MgCI2 is produced if 150 grams of Mg is used??

Answer 1

first you need to write the chemical equation of magnesium reacting with chlorine producing magnesium chloride. After, you must balance it to establish the stochiometric ratio between magnesium and magnesium chloride.

Mg(s) + Cl₂(g) ---> MgCl₂ (s)

The equation is already balanced therefore we can start setting up the problem:

150 g Mg x (1 mole Mg/24.32g Mg) x (1 mole MgCl2 / 1 mole Mg) x ( 95.31 g MgCl2 / 1 mole MgCl2)

= 586.8572604 g of MgCl2 but we must express it to two significant figures therefore the final answer is

590 g of MgCl2 or 5.9 x 10^2 grams of MgCl2