Calculate the energy in J?

Question

Calculate the energy released, in J, when 1.00 kg of uranium-235 undergoes the following fission process. ¹₀n + ²³⁵₉₂U → ¹³⁶₅₃I + ⁹⁶₃₉Y + 4¹₀n

Iodine-136: 135.8401 amu

Yttrium-96: 95.8629 amu

Uranium-235: 234.9935 amu

Neutron: 1.00867 amu

Answer 1

For 1 atom uranium-235 :

Δm = 135.8401+95.8629+4x1.00867 - (1.00867+234.9935) = -0.26449 uma

= - 0.43919594x10^-27 kg because 1 uma = 1.660538921x10^-27 kg.

So :

For 1 atom uranium-235 :

m = 234.9935x1.660538921x10^-27 = 390.215853x10^-27 kg :

Δm = -0.43919594x10^-27 kg.

For 1 kg atom uranium-235 :

m = 1.00000 kg

Δm = -1x0.43919594x10^-27/390.215853x10^-27 = -0.26449/234.9935 = -0.00112552 kg

So : E = I Δm I.C² = 0.00112552x(299792458)² = 1.01157x10¹⁴ J.