Calculate the Energy released in kj

Question

The easiest fusion reaction to initiate is ²₁H + ³₁H → ⁴₂He + ¹₀n Calculate the energy released, in kJ, per nucleus of ⁴₂He produced. The masses of the relevant particles are as follows (1 amu = 1.66×10⁻²⁷ kg):

Answer 1

Δm = 4.00260+1.00866-3.01605-2.01410 = -0.01889 amu.

So, for 1 nucleus He, we have : E = IΔmI.C² = 2.82x10^-12 J (with C = 799,792,458 m/s).

So : E = 2.82x10^-15 kJ for 1 nucleus of He.