What is S° for A in the reaction 3 A → 2 B if ∆S°(rxn) =-147.3 J/mol ･ K? [S° (B) = (240.0 J/mol ･K)]

Answer 1

∆Sº_rxn = ∑∆Sº_products - ∑∆Sº_reactants

-147.4 J/molK = (2 x 240.0 J/molK) - (3 x ∆Sº_A)

-147.4 = 480 - 3∆Sº

3 ∆Sº= +627.4

∆Sº = +209.1 J/molK

(be sure to check the math)