A rigid plastic container holds 1.00 L methane gas at 660 torr pressure when the temperature is 21.1°C. How much more pressure will the gas exert if the temperature is raised to 43.9°C?

Answer 1

If it is a rigid container then the volume doesn't change between time 1 and time 2. So the equation:

can be simplified to be:

(since v1 = v2 we can divide both sides by the volume 1.00 L and they both cancel out)

p1 = 660 torr

T1 = (21.1 + 273.15) = 294.25 K

T2 = (43.9 + 273.15) = 317.05 K

So:

660/294.25 = p2/317.05

p2 = (660)(317.25)/294.25

p2 = 711 torr

The question asks "How much more pressure will the gas exert" so I guess the answer is 711 - 660 = an additional 51 torr