Determine how many liters 8.47g of carbon dioxide gas would occupy at the following conditions.

Question

STP

140°C and 5.00 atm

239K and 109 laps

Answer 1

PV = nRT

V = nRT/P

V = 239 K *R*n/5 atm

R for when using atm is 0.082057338

n is the amount of CO₂ in moles, or 8.47 / mw of CO₂ which is 44.01 g/mol

So essentially the question becomes

V = 239 K * 8.47 g * 0.082057338 / (5 atm*44.01 g/mol)

the answer will be in liters.