Homework. Need help fast. Please and thank you

Question

At a certain temperature, the equilibrium constant for the following chemical reaction is 4.57*10^-3. At equilibrium, the concentration of AB is 1.225 M, the concentration of BC is 2.925 M, and the concentration of AC is 0.240 M. Calculate the concentration of B at equilibrium.

AB(aq) + BC(aq) = AC(aq) + 2B(aq)

Answer 1

You can use the formula, K_eq = [AC][B]² / [AB][BC], where the exponents come from the coefficients of the balanced equation.

Since you're looking for the concentration of B at equilibrium, you can rearrage the equation to solve for [B], which ends up being:

[B]² = K_eq*[AB]*[BC] / [AC] = (4.57*10^-3)(1.225 M)(2.925 M) / (0.240 M) = 0.06823

If you take the square root of [B]², you get [B] which is the concentration of B at equilibrium.

[B] = 0.261 M

Hope this helped!