Calculate how many grams of O29(g) can be produced from heating 25.7 g KCIO3(s)

Answer 1

I assume your referring to the reaction 2KClO3(s) + heat → 2KCl(s) + 3 O2(g).

We need a conversion factor relating gram O2 produced to grams KClO3 used. The factor is

(3moles O2 x Mol. Mass O2) /( 2 moles KClO3 x Mol. Mass KClO3)

(3 x 32) / (2 x 122.5) = 0.392 g O2 per gram KClO3

Multiply the factor 0.392 x 25.7 g KClO3 to get 10.1 g O2