
Yefim S. answered 03/09/24
Math Tutor with Experience
°Lowest temperature is 2·55 - 72 = 38°. Then temperature T = 17°°sin(π/6t) + 55.
At 11AM time t = -1, because we count time from 12PM. SO, T = 17sin(-π/6) + 55 = - 8.5 + 55 = 46.5°
Kimberly R.
asked 03/09/24Outside temperature over a day can be modeled as a sinusoidal function. Suppose you know the high temperature of 72 degrees occurs at 3 PM and the average temperature for the day is 55 degrees. Find the temperature, to the nearest degree, at 11 AM.
Yefim S. answered 03/09/24
Math Tutor with Experience
°Lowest temperature is 2·55 - 72 = 38°. Then temperature T = 17°°sin(π/6t) + 55.
At 11AM time t = -1, because we count time from 12PM. SO, T = 17sin(-π/6) + 55 = - 8.5 + 55 = 46.5°
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.