Chemistry - Silver Recovery

Question

Copper(II) ions can be displaced by aluminum metal.

3 CuSO4(aq) + 2 Al(s) → Al2(SO4)3(aq) + 3 Cu(s)

How many grams of Cu would be recovered from the copper ions in 49.7 mL of 0.370 M CuSO4?

g

Answer 1

M = moles / volume

So we can rewrite the equation with the given volume to find the number of CuSO4 moles:

0.370M = x moles of CuSO4 / 0.0497L (49.7ml)

x = 0.370M * 0.0497L

x = 0.0184 moles of CuSO4.

The reaction tells us that for every 3 moles of CuSO4, we produce 3 moles of Cu. (1:1 ratio)

So, 0.0184 moles of CuSO4 would give us 0.0184 moles of Cu

MM of Cu = 63.55g/mol

0.0184moles of Cu * 63.55 g of Cu / mol = 1.17 grams of Cu