67.4 grams of methane gas, ch4, and 222 grams of chlorine gas, cl2, are combined. determine the mole fraction of methane and chlorine

Answer 1

In this problem, the goal is to find the mole fraction of both chlorine gas (Cl₂) and methane gas (CH₄) when 67.4 grams of CH₄ is mixed with 222 grams of Cl₂. The first step of this problem is to find the amount of moles present for each substance.

The general formula for this is:

moles of X = (grams of X)/(Molar mass of X)

Molar mass can be calculated by adding up the atomic mass of all of the elements within a molecule. Thus for chlorine, we have:

Moles of Cl₂ = (222)/(70.9)

Moles of Cl₂ = 3.13

For methane, we have:

Moles of CH₄ = (67.4)/(16.04)

Moles of CH₄ = 4.20

Lastly, to find the mole fraction, we must divide the moles of the molecule we're looking at by the total number of moles in an environment. In this case, the total number of moles is equal to 3.13 + 4.20, or in other words 7.33.

Lastly, we plug the numbers into our equation and find the mole fraction for each molecule:

Cl₂: mole fraction = (3.13)/(7.33)

mole fraction of Cl₂ = .427

CH₄: mole fraction = (4.20)/(7.33)

mole fraction of CH₄ = .573