Using molarity to find solute mass and solution volume

Question

A chemist adds 0.75L of a 0.255M barium chloride BaCl2 solution to a reaction flask. Calculate the mass in grams of barium chloride the chemist has added to the flask. Be sure your answer has the correct number of significant digits. Put answer in grams.

Answer 1

Volume (V) = 0.75 L

Concentration (C) = 0.255 M

Molar mass of BaCl2 = 137.33 g/mol

Moles = Volume × Concentration

Moles = 0.75 L × 0.255 mol/L

Moles = 0.75 × 0.255 mol

Moles = 0.19125 mol

Mass = Moles × Molar mass

Mass = 0.19125 mol × 137.33 g/mol

Mass = 26.284 g

Rounded to the correct number of significant digits, the mass of barium chloride added to the flask is 26.3 g.