Using molarity to find solute moles and solution volume

Question

A chemist adds 165.0mL of a 0.629/molL barium chloride BaCl2 solution to a reaction flask. Calculate the millimoles of barium chloride the chemist has added to the flask. Be sure your answer has the correct number of significant digits.

Answer 1

165mL = 0.165L of BaCl2

0.165L * 0.629 mol / L = 0.104 mol of BaCl2

0.104 mol of BaCl2 * 1000 millimoles / 1 mol = 104 millimoles of BaCl2