How many GRAMS of silver chloride are present in 2.87 moles of this compound ? 411.32 grams.

Answer 1

Step 1) Write the chemical formula for silver chloride.

That would be AgCl

Step 2) Calculate the molar mass of AgCl

First look up silver and Chlorine on the periodic table:

Silver (Ag) = 107.868 g/mol

Chlorine (Cl) = 35.453 g/mol

Then multiply by the number of atoms of each and add them up:

Ag = 107.868 x 1 = 107.868

Cl = 35.453 x 1 = 35.453

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AgCl = 143.321 g/mol

Step 3) Multiply the molar mass and the number of moles:

(143.321 g/mol)(2.87 moles) = 411.33127 grams

Step 4) Round to 3 sig figs

411 grams