Chemistry Moles

Question

What would the answer be to this question? "A chemist adds 0.25L of a 0.949M sodium carbonate Na2CO3 solution to a reaction flask. Calculate the moles of sodium carbonate the chemist has added to the flask. Round your answer to 2 significant digits."

Answer 1

The equation that needs to be used for this problem would be the molarity equation [Molarity (M) = (moles of solute / Liters of solvent)

-In this case we are given the molarity of 0.949M Sodium Carbonate and the 0.25L of Sodium Carbonate.

-(M = moles/volume) can also be written as (moles = M x Volume)

-moles = 0.949M x 0.25 L = 0.23725 moles --> 0.24 moles of sodium carbonate (with two significant digits)