Chemistry (moles)

Question

What would the answer be to this question? "A chemist adds 0.25L of a 0.949M sodium carbonate Na2CO3 solution to a reaction flask. Calculate the moles of sodium carbonate the chemist has added to the flask. Round your answer to 2 significant digits."

Answer 1

This is a straightforward calculation using the definition of molarity:

molarity (mol/L) = moles solute (mol) / volume solution (L) -->

Thus, moles solute (mol) = volume solution (L) * molarity (mol/L)

Plug your values into the formula:

moles solute = 0.949 M Na2CO3 * 0.25L = 0.24 mol Na2CO3

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