What mass of sodium oxide is produced by the reaction of 1.44 g of sodium metal with oxygen according to the following unbalanced reaction?Na + O2 → Na2O

Answer 1

First you would need to balance the equation. You need to balance the O first and the Na second ending up with 4 Na on each side and 2 O. This will give you the mole ratio needed to answer the problem.

4Na + O₂ → 2Na₂O

Then convert the 1.44 g Na to moles by dividing by its molar mass.

1.44 g X (1 mol/22.99g) = 0.0626 mol Na

Then use the balanced equation to find the moles of Na₂O.

0.0626 mol Na X (2 mol Na₂O/ 4 mol Na) = 0.0313 mol Na₂O

Finally, multiply by the molar mass of sodium oxide.

0.0313 mol Na₂O X (61.98 g/mol) = 1.94 g of sodium oxide