Since 13 is prime then for any x≠0 mod 13 we have x13-1 = x12 = 1
so the equation x12 +2x+1 = 0 (mod 13)
reduces to 1+2x+1=2x+2 = 0 (mod 13).
You should get the one solution.
Or you can try each number (1 to 12) relatively prime to 13.
Adam S.
asked 12/09/23Find all the values x (mod 13) satisfying x^12 + 2x + 1 ≡ 0 (mod 13)
Since 13 is prime then for any x≠0 mod 13 we have x13-1 = x12 = 1
so the equation x12 +2x+1 = 0 (mod 13)
reduces to 1+2x+1=2x+2 = 0 (mod 13).
You should get the one solution.
Or you can try each number (1 to 12) relatively prime to 13.
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