pOH = -log([OH-}
pOH = -log(0.741)
pOH = 0.130
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 0.130
pH = 13.9 (rounded to 3 sig figs as the molarity given is the same)
Andrea R.
asked 12/08/23pOH = -log([OH-}
pOH = -log(0.741)
pOH = 0.130
pH + pOH = 14
pH = 14 - pOH
pH = 14 - 0.130
pH = 13.9 (rounded to 3 sig figs as the molarity given is the same)
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