A reaction has t=0, and t=54 min. What is the half-life of the reaction if the reaction follows first-order kinetics.

Answer 1

For a first-order half-life reaction, the equation is t_1/2 = ln 2 / k where ln 2 = 0.693, so that value may appear in some equations. Based on the info provided, k = 54, so we plug that in and get a half-life of 0.0128.