Jerome S. answered 01/08/24
PhD in Inorganic Chemistry with 10+ years of online tutoring experienc
You need to use the Nernst equation for this problem since you are no longer at standard conditions.
At standard conditions the Eo reduction of the SHE is 0.000 V at 25 C (298K)
The Nernst equation is E = Eo - RT/zF ln Q where R = 8.314 J/mol-K T = 298 K z =number of electrons transferred in the reaction = 2 and F is the Faraday constant 96485 C/mol
Q is the reaction quotient for the non standard conditions Q = (P H2)/[H+]^2
Since the pH = 5.25 H+ = 10^-5.25 = 5.62x10^-6 M
So E = 0.000 V - 8.314 J/mol-K * 298 K/ (2 * 96485 C/mol) x ln ( 1 / (5.62x10^-6)^2)
E = 0.000 V - 0.310 V = -0.310 V
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