
Breeana J. answered 03/30/15
Tutor
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AP Calculus (AB & BC) Tutor
Assuming that after 25% of the grant was appropriated for indirect costs, and 20% of what was left to buy equipment, the remainder was given to the university:
M = the original amount of grant money
Let X = indirect costs
Let Y = equipment costs
Let Z = amount of $ given to university
25% of the grant was appropriated for indirect costs:
X = 0.25M
20% of what was left was used to buy equipment:
what was left = M-X
Y = 0.2(M-X) = 0.2(M-0.25M) = 0.2(0.75M) = 0.15M
Money given to university is 80% of what was left after indirect costs (since remaining 20% used to buy equipment)
Z = 0.8(M-X) = 0.8(M-0.25M) = 0.8(0.75M) = 0.6M
We can check this by noting that X + Y + Z should add up to M
X = 0.25M, Y = 0.15M, Z = 0.6M
0.25M + 0.15M + 0.6M = M
Percent of original sum of M dollars given to university = 60%
Percent of original sum of M dollars spent on equipment = 15%
Alternate
Another way to check/solve this problem is to start with an assumed starting value of M
i.e.:
Let M = $100
25% of M = indirect costs = 0.25($100) = $25
What is left = $75
20% of $75 = equipment costs = 0.2($75) = $15
Given to university = M - indirect costs - equipment costs = $100 - $25 - $15 = $60
"What percent of original sum of M dollars was given to university?" translates into
(x%)$100 = $60 → x = 60%
"What percent of original sum of M dollars was spent on equipment?" translates into
(x%)$100 = $15 → x = 15%
(x%)$100 = $15 → x = 15%