
Bradford T. answered 11/20/23
Retired Engineer / Upper level math instructor
The hardest part of these empty-tank problems, is setting up the integral. I'll set it up for you and let you complete the integration.
Work = Force×displacement = density×volume×gravity×displacement
ρ=760 kg/m3
g = 9.8 m/s2
Want to move circular disks from the bottom of the bucket over the top of the bucket
DiskVolume = (CircleArea)dy
Work, W= ρg∫depth0(height-y)(CircleArea)dy
CircleArea = A = πr2 = πx2
y = 5ln(x-6) --> x = ey/5+6
W=ρg π∫40(8-y)(ey/5+6)2dy = ρg π∫40(8-y)(e2y/5+12ey/5+36)dy