Please Solve This Physics Problem

Question

A particle of mass 4.4 kg has position vector r = (1.9î − 2.6ĵ) m at a particular instant of time when its velocity is v = (2.6î) m/s with respect to the origin. (Express your answers in vector form.) (a) What is the angular momentum of the particle (in kg · m^2/s)? (b) If a force F = 4.4ĵ N acts on the particle at this instant, what is the torque (in N · m) about the origin?

Answer 1

ω= r x v/r² = .652k 1/s², L = I ω , I = mr², m=4.4kg and r= sqrt(1.9²+2.6²)=3.22 m thus I = 45.6 kg - m² and

L= 29.71k.k-kg/s² a)

Torque = τ = r X F = 8.36k N-m b)