a) Power = pressure x flow = ρgH*Q= 1000*9.81*21*8.4/1000= 1730 watts
b) Energy = 1730*1.9*3600=11.8E6 Joules
c) E=mgh=106/103*103*91=9.1E7 Joules
Benson A.
asked 11/14/23The pump in a water tower lifts water with a density of pw = 1.00 kg/liter from a filtered pond at the base of the tower up hT = 21 m to the top of the tower. The water begins at rest in the pond and comes to rest at the top of the tower. The pump is 100% efficient in lifting the water, and it lifts a volume of Vw = 8.4 L of water up the tower every second. The water tower sits on a hill that is Te = 95 m above sea level. Let gravitational potential energy be zero at ground level.
Part a) Calculate the power, Pp in Watts, of the pump.
Part b) If the pump runs for 1.9 hours, calculate the increase in the potential energy, ΔUw in J, of the water in the tower.
Part c) The water tower, when full, holds 106 L of water. Calculate the gravitational potential energy of the water, Uw in J, of a full water tower relative to sea level.
a) Power = pressure x flow = ρgH*Q= 1000*9.81*21*8.4/1000= 1730 watts
b) Energy = 1730*1.9*3600=11.8E6 Joules
c) E=mgh=106/103*103*91=9.1E7 Joules
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.