Please Solve This Physics Problem

Question

(a) Calculate the rotational kinetic energy (in J) of Venus on its axis. (Assume its mass to be 4.90 ✕ 10²⁴ kg, the period about its axis to be 5830 h, and its diameter to be 12100 km.) (b) What is the rotational kinetic energy (in J) of Venus in its orbit around the Sun? (Assume its distance from the sun to be 1.08 ✕ 10⁸ km and its period about the sun to be 225 days.)

Answer 1

1/2I ω² = rot KE

I_axis=2/5mr²= 2/5*4.9E24*(12100/4)²=7.17E13, ω_axis=2π/5850/3600=2,98E-7. rad/sec

KE_axis= 1/2*7.17E13(2.98E-7)²=3.19E-14 J

I_sun=mr²= 4.9E24*(1.08E11)²= 5.72E46 kg-m², ω_sun=2π/225/24/3600=3.23E-7 rad/sec

KE_sun=1/2(5.72E46)*(3.23E-7)²=2.98E31 J