Calculate the percent yield from the reaction below.

Question

Na₂CO₃ + CaCl₂ ---- > NaCl + CaCO₃

If you reacted 10.1 grams of Na₂CO₃ with CaCl₂ and you collected 5.60 grams of CaCO₃, what is your percent yield?

Answer 1

Na₂CO₃ + CaCl₂ --> 2 NaCl + CaCO₃ (Stoichiometry Na₂CO₃:CaCO₃ = 1:1)

If you assume that the limiting reagent is Na₂CO₃ ;

Theoritical amount of CaCO3 can be formed = [(10.1 g)/ (105.99 g mol^-1)_Na2CO3] x (100.087 g mol^-1)_CaCO3

= 9.55 g

% Yield = (5.60 g/ 9.55 g) x 100%

= 58.6%