Enter the solubility - product expression for Al(OH)3 (s).

Question

Enter the solubility - product expression for Al(OH)₃ (s).

K_sp= ?

Answer 1

Al(OH)3 → A3+ + 3 (OH)1-

Ksp = [Al3+] [OH1-]^3

Upon dissociation, the [OH1-] = 3 [Al3+], so the expression reduces to

Ksp = S x (3S)^3 = 27S^4 where S = concentration of Al3+.at equilibrium.