1) Conservation of momentum 80vxqi+.43vxfi=80vxqf+.43vxff=0 since vxqi & vxfi=0.
2) Solve to find vxqf=-.43*15/80=-.0813 m/s
Lauren M.
asked • 11/06/23Football physics problem-please help I am stuck on this!
An 80-kg quarterback jumps straight up in the air right before throwing a 0.43-kg football horizontally at 15 m/s. - How fast, (Vqx)f will the quarterback be moving backward just after releasing the ball?
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Lauren M.
Thank you for your help! Would you also be able to help me with the second part of this? - Suppose that the quarterback takes 0.30 s to return to the ground after throwing the ball. How far (d) will he move horizontally, assuming his speed is constant?11/06/23