if 0.178 mol of zinc reacts with excess lead (IV) sulfate, how many grams of zinc sulfate will be produced in the reaction

Answer 1

First, write a balanced chemical equation for the reaction:

Lead IV has a 4+ charge and Sulfate has a 2- charge. Zinc has a 2+ charge.

Pb(SO₄)₂ + 2Zn →2ZnSO₄ + PB

Next, use stoichiometry to predict how many moles of product will be produced.

For every 2 moles of zinc reacted, 2 moles of zinc sulfate will be produced. So we should expect to produce 0.178 mol of Zinc Sulfate.

Next, we need to convert our answer from moles to grams. We can do this by using the molar weight of Zinc Sulfate.

MW = 161.47 g/mol

m = 161.47 g/mol * (0.178 mol)

m = 28.74 g