1 pOH = -log([OH-] = -log(7.6x10-6)
pOH = 5.119
pOH + pH = 14.00
therefore, pH = 14.00-5.119 = 8.88
So, this solution is basic
2 pH 12.06 is basic
3 pH 7.00 is neutral
4 pH = -log([H+]) = -log(1.0x10-7)
= 7.00
this solution is neutral
Kylie Z.
asked 11/04/23Classify each aqueous solution as acidic, base, or neutral at 25 ° C.
1 pOH = -log([OH-] = -log(7.6x10-6)
pOH = 5.119
pOH + pH = 14.00
therefore, pH = 14.00-5.119 = 8.88
So, this solution is basic
2 pH 12.06 is basic
3 pH 7.00 is neutral
4 pH = -log([H+]) = -log(1.0x10-7)
= 7.00
this solution is neutral
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.