Michael X. answered 11/04/23
Veteran Tutor for Bio/Chem/Math; SAT/ACT/College App Advising
The balanced equation is as follows:
HBr (aq) + NaOH (s) --> NaBr (aq) + H2O (aq)
Convert the mass quantities of the reactants into molar quantities:
3.2 g HBr/80.91 g/mol = 0.0396 mol HBr
2.4 g NaOH/40.00 g/mol = 0.06 mol NaOH
Because the coefficients in the reaction are all one and the molar quantity of HBr is less than that of NaOH, HBr is the limiting reagent, and thus 0.0396 mol NaBr is formed.
Obtain the mass of NaBr formed:
0.0396 mol * 102.894 g/mol = 4.1 g NaBr
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