Ishwar S. answered 11/03/23
University Professor - General and Organic Chemistry
Reaction 1: HPO42- + H+ ⇌ H2PO4-
In reaction 1, H+ is a Bronsted-Lowry acid (proton donor) and HPO42- is a B-L base (proton acceptor). To HPO42-, you are adding 1 hydrogen with a charge of +1. Therefore, in the chemical formula of the product, the # of hydrogens increases by 1 (H2) and the overall charge is obtained by adding (-2) + 1 = -1.
Reaction 2: HPO42- + OH- ⇌ PO43- + H2O
In reaction 2, HPO42- is a Bronsted-Lowry acid (proton donor) and OH- is a B-L base (proton acceptor). On the product side, PO43- is the conjugate base of HPO42-, and H2O is the conjugate acid of OH-.
Hope the above was helpful!