How many grams of N3 are required to complete the reaction with 3.03 grams of H2 for the following chemical equation? N2 + H2 -> NH3

Answer 1

Finding the Required Mass of N2 for a Chemical Reaction

Step 1: Balance the Chemical Equation

Given Reaction:

N2 + 3H2 -> 2NH3

Step 2: Convert grams of H2 to moles

- Molar mass of H2 = 2.02 g/mol

- Moles of H2 = 3.03 g / 2.02 g/mol = 1.5 moles

Step 3: Use mole ratio to find moles of N2

- The balanced equation shows a 3:1 mole ratio between H2 and N2.

- Moles of N2 = 1.5 moles H2 * (1 mole N2 / 3 moles H2) = 0.5 moles of N2

Step 4: Convert moles of N2 to grams

- Molar mass of N2 = 28.02 g/mol

- Grams of N2 = 0.5 moles * 28.02 g/mol = 14.01 grams

Conclusion:

You would need 14.01 grams of N2 to completely react with 3.03 grams of H2 according to the balanced chemical equation.