oxygen can be prepared in the laboratory by heating potassium chlorate. The reaction is 2KClO3 -> 2KCl + 3O2. How many grams of O2 could be obtained from 2 mole of KClO3?

Answer 1

Finding the Mass of O2 Produced from KClO3

Step 1: Balance the Chemical Equation

2KClO3 -> 2KCl + 3O2

Step 2: Use Mole Ratio to Find Moles of O2

The balanced equation shows a 2:3 mole ratio between KClO3 and O2.

Moles of O2 = 2 moles KClO3 * (3 moles O2 / 2 moles KClO3) = 3 moles of O2

Step 3: Convert Moles of O2 to Grams

Molar mass of O2 = 32.00 g/mol

Grams of O2 = 3 moles * 32.00 g/mol = 96.00 grams

Conclusion:

From 2 moles of KClO3, you could obtain 96.00 grams of O2 according to the balanced chemical equation.