Solving limiting reactant problems in solution

Question

Suppose 29.0g of sodium chloride is dissolved in 300.mL of a 0.70 M

 aqueous solution of potassium carbonate. Calculate the final molarity of chloride anion in the solution. You can assume the volume of the solution doesn't change when the sodium chloride is dissolved in it.

Be sure your answer has the correct number of significant digits.

Answer 1

NaCl + K₂CO₃ --> Na⁺ + Cl^- + K₂CO₃

29.0 g NaCl/58.44 g/mol = 0.496 mol

Since NaCl dissolves into Na+ and Cl-, 0.496 mol Cl- are formed

0.496 mol Cl-/0.300 L = 1.65 M Cl-