
Anthony T. answered 10/25/23
Patient Science Tutor
I will do the first one for you, then you should be able to do the others yourself.
The Henderson-Hasselbalch equation is pH = pKa + log conjugate base/ conjugate acid.
We need to know the pH desired for the buffer which was given as 5.00. A table of pKa of weak acids was consulted on line and I found acetic acid at a pKa of 4.76 which is reasonably close to the desired pH. Now, all we have to do is plug these numbers into the equation and solve for log conjugate base/ conjugate acid.
So, 5.00 = 4.76 + log Ac-/ HAc
log Ac-/ HAc = 5.00 - 4.76 = 0.24
Ac- / HAc = antilog of 0.24 which is 1.74, but the question asks for the ration of acid to conjugate base, so we need to invert the result to get 1/1.74 = 0.575.
The remaining problems can be done similarly.