The standard heat of formation for Be(OH)2(s) is -903 kJ/mol at 298 K. Write the formation equation for Be(OH)2(s) that goes with this value of ΔH°.

Answer 1

Remembering that the standard heat of formation of one mole of the compound from its elements in their natural states, the equation should reflect Be (s), Hydrogen (2 atoms) and oxygen (2 atoms)

The equation then is

Be(s) + H₂(g) + O₂(g) → Be(OH)₂(s) ΔH^o = -903 kJ/mol