This is a binomial distribution problem. The formula is:
P(r) = nCr · pr (1 − p)n−r.
where P(r) is the probability of exactly r successes out of n attempts, with p= the probability of a single success.
( nCr is the number of combinations of n items taken r at a time.)
In our case, r=6, n=8, and p=0.49.
So,
P(x) = [8!/(6!×2!)] × (0.49)6 × (1 - 0.49)8-6
= (8*7/2) × (0.49)6 × (0.51)2
= 0.1008 to four decimal places of accuracy.