How many grams of CaCl2 are needed to make 229.4 g of a solution that is 35.0% (m / m) calcium chloride in water?

Answer 1

We have 229.4 g of solution.

35% m/m calcium chloride is equivalent to (35 g CaCl₂ ) / (100 g solution).

Thus, (229.4 g solution) x (35 g CaCl₂/100 g solution) = 80.29 g CaCl₂

Final Answer: 80.29 g CaCl₂ are needed