William C. answered 10/18/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
H–F has a polar bond to an H atom, so
hydrogen bonding, dipole–dipole, and dispersion
C≡O is tricky because the CO bond is essentially nonpolar despite the electronegativity difference between C and O. The dipole resulting from this
electronegativity difference is counterbalanced by electron donation from O to C. So
dispersion only
He had no bonds, therfore no polar bonds, so
dispersion only
H3C–Cl has a polar C–Cl bond, but neither atom is a H, so
dipole–dipole, and dispersion