Nurit H. answered 10/15/23
MD student with 8+ years tutoring experience
KE=1/2 mv^2
KE=kinetic energy
m=mass (in kg)
v= velocity in m/s
132=1/2(1.25E-3)v^2
v=459m/s
Mary H.
asked 10/15/23A 1.25 g sample of helium gas at 25°C has a KE of 132 J. What is the average molecular velocity of the gas? Report your answer in meters per second to the nearest whole number.
Nurit H. answered 10/15/23
MD student with 8+ years tutoring experience
KE=1/2 mv^2
KE=kinetic energy
m=mass (in kg)
v= velocity in m/s
132=1/2(1.25E-3)v^2
v=459m/s
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