
William W. answered 10/11/23
Math and science made easy - learn from a retired engineer
First determine the reactants and products.
Start with barium carbonate. The carbonate ion is CO3-2 so the barium carbonate compound would be BaCO3
If looking for a precipitate, I would look at a double replacement reaction. Looking at a solubility table, you would see something like this for the carbonate (CO3-2) column:
This shows that sodium carbonate is aqueous in solution so it becomes a possible reactant. It doesn't take much to consider barium chloride as the the other reactant (the solubility table also shows this as aqueous in solution. So a POSSIBLE double replacement chemical reaction equation would be:
BaCl2(aq) + Na2CO3(aq) → BaCO3(s) + 2NaCl(aq)
This is called the molecular or balanced equation.
The ionic equation would be:
Ba+2(aq) + 2Cl-(aq) + 2Na+(aq) + CO3-2(aq) → BaCO3(s) + 2Na+(aq) + 2Cl-(aq)
because all the aqueous compounds disassociate in solution.
To get the net equation, just remove the ions that are the same on both sides:
Ba+2(aq) + CO3-2(aq) → BaCO3(s)