William C. answered 09/26/23
Experienced Tutor Specializing in Chemistry, Math, and Physics
for a zero order reaction A → products we have d[A]/dt = –k leading to
[A] = –kt + [A]₀ where t = time (in s) and k = the rate constant (in M/s)
The value of t when [A]/[A]₀ = ½ is called the half life of the reaction and is represented as t½
The relationship between half life (t½) and rate constant (k) can be found by writing the expression
½[A]₀ = –kt½ + [A]₀ and solving for t½
Adding kt½ – ½[A]₀ to both sides gives kt½ = [A]₀ – ½[A]₀ = ½[A]₀ which means that
t½ = [A]₀/2k or k = [A]₀/2t½
In the problem we're given a rate constant 0.737 M-1s-1
(The units are wrong here; they should be 0.737 M s-1)
Question 1
What is the half-life given an initial concentration of 1.75 M?
t½ = [A]₀/2k = (1.75)/(2 × 0.737) = 1.187 s
Question 2
How much of the substance remains after 22.5 seconds? 101 seconds?
[A] = –kt + [A]₀
The decay is linear, not exponential. After two half lives (2.374 s) all of the substance is gone. So for any time t ≥ 2.374 s, [A] = 0.
Answer
There is no substance left after 22.5 seconds.
There is no substance left after 101 seconds.
The Last Question
I also want to know that for the answers that i get for each seconds, is it supposed to be negative because the substance is decaying?
The concentration can't be negative. The lowest number possible for concentration is zero.